Ummm... No you're wrong. 18% of 210 is 37.8. Ok now seriously. You need you calculate drivetrain loss from the crank HP value which I dont have. So let's do a little algebra.

Let x = Crank HP value.

Let y = WHP value.

At 18% y = .82x in other words WHP is 82% of crank HP. (100-18=82)

We know from the dyno that y=210

So 210 = .82x

Now, divide both sides by .82

Now 210/.82 = x

So x = 256 hp

A similar method can be used to calculate torque. Just letting you know.