Ummm... No you're wrong. 18% of 210 is 37.8. Ok now seriously. You need you calculate drivetrain loss from the crank HP value which I dont have. So let's do a little algebra.
Let x = Crank HP value.
Let y = WHP value.
At 18% y = .82x in other words WHP is 82% of crank HP. (100-18=82)
We know from the dyno that y=210
So 210 = .82x
Now, divide both sides by .82
Now 210/.82 = x
So x = 256 hp
A similar method can be used to calculate torque. Just letting you know.