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      03-07-2006, 07:11 PM   #2
ksfrogman
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Drives: E90 330i 6MT
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Well, I found something that essentially is something like this. Correct me if I am wrong.

Let Q = stiffness in lbs/inch
C = Constant
D = Roll bar diameter
L = Length of bar
A = Length of lever arm

Q = C * D^4/[L*A^2]

So stiffness is directly proportional to diameter ^4
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