[AltecBX]

I've been searching around the forums and know that methanol increases octane level. Our 335 fuel tank holds a total of 16.1 gal. People that fill their tanks with 91 octane say that the level of octane will be 103 when injecting methanol while they drive. Same thing with people that fill with 93 oct, they state that they have levels of 105-108 octane. Guys running methanol can drop ignition correction to 0%. People can run these settings and use up 4 quarts of methanol with a full 16 gal tank of gas driving aggressively.

I know the more 100 octane you add to your gas tank, the better. My question is how much 100 octane fuel gallons is necessary to bring down the Ign Correction to 0% as well without using methanol. (93 octane right is $3.29 a gal & $7.99 for 100 oct. Basically, how much gallons of 100 oct do I mix to 93 oct to match that of methanol.
So with a meth setup driving aggressively the whole time per tank, you’ll be paying $52.64 (16 gal x 3.29) and $10.20 for methanol. A total of $62.84 will be spent to drive a tank of gas running 0% of ignition correction.

What’s the minimum amount of 100 octane to mix with 93 oct to get 0% ign correction running just as good as methanol injection?