View Single Post
      09-10-2013, 12:37 PM   #2
RandomHero
Private First Class
United_States
25
Rep
159
Posts

Drives: 2008 335i e92
Join Date: Apr 2013
Location: Austin,tx

iTrader: (0)

EDIT- I'm wrong

EDIT 2-

the limit exists when -5<x<-3 and -3<x<2

The limit is defined -6<f(x)<0 and 0<f(x)<1

discontinuity when x=-3

let's go with that.

Last edited by RandomHero; 09-10-2013 at 01:12 PM..
Appreciate 0