Help with small problem solving puzzle

Manny212 · 10-10-2007, 12:10 AM

My science teacher game me this small puzzle to figure out and it counts as a quiz...This is the lamest core class ever BTW and i feel dumb doing these problem solving puzzles. Anyway here it is:

Four people (M, N, O, P) each own a cat and a dog. Each cat and dog is named after one of the people, but no pet is named after its owner. P's dog and O's cat are both named after the owner of the cat named O. The namesake of N's cat is the owner of the cat whose namesake owns the dog named M.

I need to solve that...so far i got:

M's cat = O
dog = ?

N's cat = P
Dog = O...just figured this one out i think

O's cat = M
dog = ?

P's cat = N
dog = M

Kiemyster · 10-10-2007, 12:55 AM

how, in hell, will this every apply to real world situations? lol. where do u go? NYU?

honestly, for my field of work, all i ever needed was pre algebra, stats, and english to excel at it lol

and no. im sorry i cant be of help...

FirstClass · 10-10-2007, 01:06 AM

You never did these in school? My gifted teacher gave these to us all the time, you need to make a grid and play with X's.

Kiemyster · 10-10-2007, 01:12 AM

meh, i got them in my geometry classes. but i made a deal with my teacher under the table lol... basically, i hooked him up with some car parts, in return, the answers to the work lol. i would walk in school early, go to his desk, and just pick it up, and head to my class ahahah

Nikki · 10-10-2007, 01:14 AM

Is that all the exact wording from the problem?

FirstClass · 10-10-2007, 01:29 AM

What you have posted there for your solution is wrong methinks.

Nikki · 10-10-2007, 02:20 AM

Did it say if any of the people couldn't have their dog and cat named the same thing?

This is what i got:

MC= O
MD=O

NC=P
ND=P

OC=M
OD=N

PC=N
PD=M

Manny212 · 10-10-2007, 09:07 AM

hmm i've been getting different answers all across the board.

Nikki, yes thats the exact wording, worded poorly IMO and so there have to be assumptions as to what goes where. I'm assuming an owner wouldn't name both pets the same name. I agree with whoever said i'll never be using this in life. I struggle with these core classes because they are a waste of time and bore the hell out of me.

HyperM3 · 10-10-2007, 10:19 AM

Quote:

Originally Posted by Manny212

I agree with whoever said i'll never be using this in life.

Actually, as absurd as something like this is, it teaches you resourcefulness. You are doing exactly what youre supposed to, whether or not you get the answer correct. Youre getting the fundementals of how to use outside help in obtaining information.

MadDog · 10-10-2007, 10:39 AM

These type of problems require you to do some thinking.

Try this problem:

A dark night. Aaron, Bill, Cliff, and Doug are on one side of a bridge, with only one flashlight. The bridge can at most hold only two people at a time. Each of the kids have their own walking speeds but they need to share a flashlight, so a pair must go as slow as the slowest one. Individually:

Aaron takes 1 minutes to cross the bridge
Bill takes 2 minutes to cross the bridge
Cliff takes 5 minutes to cross the bridge
Doug takes 10 minutes to cross the bridge

What is the lowest amount of time for all four to cross the bridge ??

And post your solution....

MadDog · 10-10-2007, 10:41 AM

Quote:

Originally Posted by HyperM3

Actually, as absurd as something like this is, it teaches you resourcefulness. You are doing exactly what youre supposed to, whether or not you get the answer correct. Youre getting the fundementals of how to use outside help in obtaining information.

Having someone post the answer for you is the easy way out. How do you learn anything from that ??

sipark · 10-10-2007, 10:49 AM

Quote:

Originally Posted by MadDog

These type of problems require you to do some thinking.

Try this problem:

A dark night. Aaron, Bill, Cliff, and Doug are on one side of a bridge, with only one flashlight. The bridge can at most hold only two people at a time. Each of the kids have their own walking speeds but they need to share a flashlight, so a pair must go as slow as the slowest one. Individually:

Aaron takes 1 minutes to cross the bridge
Bill takes 2 minutes to cross the bridge
Cliff takes 5 minutes to cross the bridge
Doug takes 10 minutes to cross the bridge

What is the lowest amount of time for all four to cross the bridge ??

And post your solution....

(10 & 1) 10 + 1
(2 & 1) 2 + 1
(5 & 1) 5

= 19 mins

MadDog · 10-10-2007, 10:50 AM

Quote:

Originally Posted by sipark

(10 & 1) 10 + 1
(2 & 1) 2 + 1
(5 & 1) 5

= 19 mins

Wrong answer. Try again.

HyperM3 · 10-10-2007, 10:50 AM

Here try this:

MC=O
MD=P

NC=P
ND=O

OC=M
OD=N

PC=N
PD=M

HyperM3 · 10-10-2007, 10:53 AM

Quote:

Originally Posted by MadDog

Having someone post the answer for you is the easy way out. How do you learn anything from that ??

Deligation and resourcefulness. Why do you think CEO's are where they are at? They have VP's who are very good at doing the work for them.

boostedbavarian · 10-10-2007, 11:22 AM

Quote:

Originally Posted by MadDog

These type of problems require you to do some thinking.

Try this problem:

A dark night. Aaron, Bill, Cliff, and Doug are on one side of a bridge, with only one flashlight. The bridge can at most hold only two people at a time. Each of the kids have their own walking speeds but they need to share a flashlight, so a pair must go as slow as the slowest one. Individually:

Aaron takes 1 minutes to cross the bridge
Bill takes 2 minutes to cross the bridge
Cliff takes 5 minutes to cross the bridge
Doug takes 10 minutes to cross the bridge

What is the lowest amount of time for all four to cross the bridge ??

And post your solution....

17mins...
________
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Rhode Island Marijuana Dispensary
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WILDTITSXX
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How to roll a blunt

Manny212 · 10-10-2007, 11:55 AM

Quote:

Originally Posted by HyperM3

Here try this:

MC=O
MD=P

NC=P
ND=O

OC=M
OD=N

PC=N
PD=M

i believe thats the right one. I originally did it on my own but got:

MC=O
MD=N

NC=P
ND=O

OC=M
OD=P

PC=N
PD=M

so while i was close i was slightly off...i'm really not very good at solving these things and thats why i asked for help. Not like i didn't try and just wanted the answer...i just wanted to make sure i got the right answer so i dont fail something like this.

HyperM3 · 10-10-2007, 11:58 AM

Quote:

Originally Posted by Manny212

i believe thats the right one. I originally did it on my own but got:

MC=O
MD=N

NC=P
ND=O

OC=M
OD=P

PC=N
PD=M

so while i was close i was slightly off...i'm really not very good at solving these things and thats why i asked for help. Not like i didn't try and just wanted the answer...i just wanted to make sure i got the right answer so i dont fail something like this.

Its all good man, no worries. Its funny how people can say that nobody should get a free answer and yet Im sure theyve done it themselves in the past. Those who live in glass houses...

Dleo · 10-10-2007, 12:08 PM

Quote:

Originally Posted by MadDog

These type of problems require you to do some thinking.

Try this problem:

A dark night. Aaron, Bill, Cliff, and Doug are on one side of a bridge, with only one flashlight. The bridge can at most hold only two people at a time. Each of the kids have their own walking speeds but they need to share a flashlight, so a pair must go as slow as the slowest one. Individually:

Aaron takes 1 minutes to cross the bridge
Bill takes 2 minutes to cross the bridge
Cliff takes 5 minutes to cross the bridge
Doug takes 10 minutes to cross the bridge

What is the lowest amount of time for all four to cross the bridge ??

And post your solution....

edit= tell doug to loose some weight

3onDubs · 10-10-2007, 12:10 PM

This is a typical LSAT question...

MadDog · 10-10-2007, 12:12 PM

Quote:

Originally Posted by boostedbavarian

17mins...

Solution ??

Dleo · 10-10-2007, 12:23 PM

Aaron crosses with Bill, Aaron goes back across (2 minutes + 1 minute).
Cliff crosses with Doug, Bill goes back across (10 minutes + 2 minutes).
Aaron crosses with Bill (2 minutes)
2+1+10+2+2 = 17 minutes

10-10-2007, 12:10 AM	#1
Manny212 Captain 62 Rep 666 Posts Drives: 2008 M3 Join Date: Apr 2007 Location: NY iTrader: (3)	Help with small problem solving puzzle My science teacher game me this small puzzle to figure out and it counts as a quiz...This is the lamest core class ever BTW and i feel dumb doing these problem solving puzzles. Anyway here it is: Four people (M, N, O, P) each own a cat and a dog. Each cat and dog is named after one of the people, but no pet is named after its owner. P's dog and O's cat are both named after the owner of the cat named O. The namesake of N's cat is the owner of the cat whose namesake owns the dog named M. I need to solve that...so far i got: M's cat = O dog = ? N's cat = P Dog = O...just figured this one out i think O's cat = M dog = ? P's cat = N dog = M __________________ 2008 E92///M3 - \| Alpine White/Fox Red Extended Novillo \| Technology \| Premium \| Cold \| Mods: \| 19" Avante Garde \| Macht Schnell Filter \| RPi Scoops \| Rogue SSK \| MS Spacers \| ACM Test Pipes \| ESS Tune \| Remus Race \| LUX V4 Angels \| KW V3 \|
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10-10-2007, 12:55 AM	#2
Kiemyster Bimmerpost Resident Marijuana Consultant 448 Rep 3,197 Posts Drives: 320i, 325xi, 335Xi, 335i, M3 Join Date: Nov 2006 Location: Queens/NYC iTrader: (4) Garage List 2010 BMW 335i [0.00] 2011 BMW X335i [0.00] 2006 BMW E90 325xi [0.00] 2011 BMW E90 335xi [4.00] 2011 BMW M3 E90 [7.00] 2006 E90 320i [0.00]	how, in hell, will this every apply to real world situations? lol. where do u go? NYU? honestly, for my field of work, all i ever needed was pre algebra, stats, and english to excel at it lol and no. im sorry i cant be of help... __________________ "AMG What! S-Line Who? If you ain't got that M I got no respect for you!" '06 Alpine Weiss E90 320i \| '06 The Green Machine E90 325xi \| '11 Alpine Weiss E90 M3 ZCP \| '10 Silverstone X5M \| '11 Alpine Weiss E90 335xi
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10-10-2007, 01:12 AM	#4
Kiemyster Bimmerpost Resident Marijuana Consultant 448 Rep 3,197 Posts Drives: 320i, 325xi, 335Xi, 335i, M3 Join Date: Nov 2006 Location: Queens/NYC iTrader: (4) Garage List 2010 BMW 335i [0.00] 2011 BMW X335i [0.00] 2006 BMW E90 325xi [0.00] 2011 BMW E90 335xi [4.00] 2011 BMW M3 E90 [7.00] 2006 E90 320i [0.00]	meh, i got them in my geometry classes. but i made a deal with my teacher under the table lol... basically, i hooked him up with some car parts, in return, the answers to the work lol. i would walk in school early, go to his desk, and just pick it up, and head to my class ahahah __________________ "AMG What! S-Line Who? If you ain't got that M I got no respect for you!" '06 Alpine Weiss E90 320i \| '06 The Green Machine E90 325xi \| '11 Alpine Weiss E90 M3 ZCP \| '10 Silverstone X5M \| '11 Alpine Weiss E90 335xi
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10-10-2007, 01:14 AM	#5
Nikki Major General 985 Rep 6,381 Posts Drives: Sepang Z4MC Join Date: Aug 2005 Location: LA iTrader: (9)	Is that all the exact wording from the problem? __________________ Nikki
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10-10-2007, 02:20 AM	#7
Nikki Major General 985 Rep 6,381 Posts Drives: Sepang Z4MC Join Date: Aug 2005 Location: LA iTrader: (9)	Did it say if any of the people couldn't have their dog and cat named the same thing? This is what i got: MC= O MD=O NC=P ND=P OC=M OD=N PC=N PD=M __________________ Nikki
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10-10-2007, 09:07 AM	#8
Manny212 Captain 62 Rep 666 Posts Drives: 2008 M3 Join Date: Apr 2007 Location: NY iTrader: (3)	hmm i've been getting different answers all across the board. Nikki, yes thats the exact wording, worded poorly IMO and so there have to be assumptions as to what goes where. I'm assuming an owner wouldn't name both pets the same name. I agree with whoever said i'll never be using this in life. I struggle with these core classes because they are a waste of time and bore the hell out of me. __________________ 2008 E92///M3 - \| Alpine White/Fox Red Extended Novillo \| Technology \| Premium \| Cold \| Mods: \| 19" Avante Garde \| Macht Schnell Filter \| RPi Scoops \| Rogue SSK \| MS Spacers \| ACM Test Pipes \| ESS Tune \| Remus Race \| LUX V4 Angels \| KW V3 \|
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10-10-2007, 10:39 AM	#10
MadDog Careful, I Bite..... 153 Rep 504 Posts Drives: 2006 325i Join Date: Dec 2006 Location: S.F. Bay Area iTrader: (0) Garage List 2006 325i [7.50]	These type of problems require you to do some thinking. Try this problem: A dark night. Aaron, Bill, Cliff, and Doug are on one side of a bridge, with only one flashlight. The bridge can at most hold only two people at a time. Each of the kids have their own walking speeds but they need to share a flashlight, so a pair must go as slow as the slowest one. Individually: Aaron takes 1 minutes to cross the bridge Bill takes 2 minutes to cross the bridge Cliff takes 5 minutes to cross the bridge Doug takes 10 minutes to cross the bridge What is the lowest amount of time for all four to cross the bridge ?? And post your solution....
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10-10-2007, 10:50 AM	#14
HyperM3 Too many Alex's, from now on, call me Beaufort 342 Rep 6,188 Posts Drives: See Sig Join Date: Feb 2007 Location: Lawrenceville, NJ iTrader: (8)	Here try this: MC=O MD=P NC=P ND=O OC=M OD=N PC=N PD=M __________________ 13 HD FatBob 17 A4 Glacier/Black 1st Edition/Pre+/Sport/EurocodeTMD/Racechip 16 S6 (gone),14 S6 (gone),14 S6 (gone),13 S6 (gone),10 S4 (gone) 07 335i(gone)
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10-10-2007, 12:10 PM	#20
3onDubs You live by the sword... 216 Rep 8,244 Posts Drives: M4 Join Date: Oct 2007 Location: OC iTrader: (3) Garage List 2007 328i [0.00]	This is a typical LSAT question...
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10-10-2007, 12:23 PM	#22
Dleo Brigadier General 210 Rep 3,358 Posts Drives: 2010 X5 Join Date: Jul 2006 Location: NYC iTrader: (2)	Aaron crosses with Bill, Aaron goes back across (2 minutes + 1 minute). Cliff crosses with Doug, Bill goes back across (10 minutes + 2 minutes). Aaron crosses with Bill (2 minutes) 2+1+10+2+2 = 17 minutes __________________
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